Question

simplify the complex fraction (let's see if I can translate the format so it's understandable):
(1/y) -3
over
(1/y^3) -9
= ??

Answer 1

\[\frac{\frac{1}{y}-3}{\frac{1}{y^3}-9}\]

Answer 2

like that?

Answer 3

multiply top and bottom by
\[y^3\] to get
\[\frac{y^2-3y^3}{1-9y^3}\]

Answer 4

\[(-2/y)/8y^3/9\]
=9/(4Y^2)

Answer 5

(1/y - 3y/y)/(y^3/y^3 - y^3/9)