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Mathematics 22 Online
OpenStudy (anonymous):

Find the following product: (y^2 – 2y – 6) (y + 5)

OpenStudy (anonymous):

do you know how to foil?

OpenStudy (anonymous):

not really

jimthompson5910 (jim_thompson5910):

(y^2 – 2y – 6) (y + 5) (y + 5)(y^2 – 2y – 6) y(y^2 – 2y – 6)+5(y^2 – 2y – 6) y(y^2) +y( – 2y) +y( – 6)+5(y^2) +5(– 2y)+5( – 6) y^3-2y^2-6y+5y^2-10y-30 y^3+3y^2-16y-30 So (y^2 – 2y – 6) (y + 5)=y^3+3y^2-16y-30

OpenStudy (anonymous):

Alright, foiling is a very important technique in math.what you want to do is take the first term in your first equation/polynomial and multiply it with (y+5). so you'd do \[y^2(y+5)\] which would equal \[y^3+5y^2\]. Then you want to take the second term in your first equation and multiply it to the other equation and the last term with the other question. Then simplify. Add like terms

OpenStudy (anonymous):

hank you

OpenStudy (anonymous):

thank you

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