Find the equation of the circle passing through the points (-4,-2) and (2,0) and having its center on the line 5x-2y=19. I need two forms of answer... general and standard... its okay if you give me a general equation b'coz I knew already how to convert general equation to standard.
how is your work finding last digit of pi ?
wow... until now you still remembered it?
wow indeed lol
the eq of the circle will b (x-x1)^2+(y-y1)^2=r^2 since the points given r in the circle they prove the eq of the circle and since the center is in the line 5x-2y=19 then its coordinates prove the eq of the circle... so we can form the system (-4-x1)^2+(-2-x1)=r^2 (2-x1)^2+(0-y1)^2=r^2 5x1-2y1=19
what about the general eq.
hmm....isn't this the general eq?
the general eq. is this x^2+y^2+Dx+Ey+F=0
well after u've found the eq (x-x1)^2+(y-y1)^2=r^2 all u have to do is transform it x^2-2xx1-x1^2...etc...and this is how i get it
the standard eq. is this\[(x+h)^{2}+(y+k)^{2}=0\]
I think you've used the calculus in solving this problem.
I think that's conic
tht's conic....
http://www.wolframalpha.com/input/?i=solve+the+system+%28-4-x1%29^2%2B%28-2-x1%29%3Dr^2%3B+++%282-x1%29^2%2B%280-y1%29^2%3Dr^2%3B++5x1-2y1%3D19 this is wht Wolfram says
That's a sort of "help" formula based on completing the square..
oh my brain malfunctioned that is the general equation sorry
Your brain didn't malfunction, it isn't standard, just meant to help the student...
Thanks estudier : )
I don't like questions like this ...
I still think the simplest method for solving this sort of thing is to translate to the origin but I suppose that might be going beyond....
eaularch just use the formulas distance one then convert it into any equation you like
what is that is that really way beyond translate
okay you're saying make the center 0,0 right?
Everything is just much easier to calculate at (0,0)..
oh okay
Then when u got it, translate it back..
Anyway, I am just trying to think of a simple way to explain...(without translation).
yeah thanks I will try this tonight thanks estudier these type of questions are asked a lot in india especially in IIT,AIEEE exams (for entering top colleges in India) I will try this. Thanks I gotta go now bye and thanks estudier
Ciao!
Estudier it is easier if the center was at (0;0) but it is not ;/
It's just a translation, quite simple.
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