Question

2x^2-3x-1=0
solve and show working

Answer 1

ready?

Answer 2

you want to use
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with
\[a=2,b=-3,c=-1\]

Answer 3

you get
\[x=\frac{3\pm\sqrt{(-3)^2-4\times 2\times (-1)}}{2\times 2}\]

Answer 4

\[x=\frac{3\pm\sqrt{9+8}}{4}\]
\[x=\frac{3\pm\sqrt{17}}{4}\] done