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need help finishiing a problem x^2-10x+25=0 a=1 b=-10 c=25 10+-(square root)100-100/2
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\[(x-5)^2\] \[x=5\]
a=1 b=-10 c=25 is correct (x-5)^2 = 0 x = 5
Where'd you get stuck Brittany?
10±{-10^2-4(1)(25)}/2 {} stands for square root cos idont have a square root symbol
then i simplified and got 10±/2
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That's \[\frac{10 \pm 0}{2} = \frac{10}{2} = 5\]
and its only one answer? usually its like x = # or #
Right, but in this case it's not because the part in the square root became a 0. Only if the square root part is non-zero do you get two solutions (one for the plus and one for the minus)
thankyou :)
polpak can you help me with http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4e4970570b8b8d00ebe389b9
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