Question

how do i write the point-slope for and the slope-intercept form of the equation of the line passing through (-1,60 with the slope of -4?

Answer 1

y = mx + c
m=-4
y =-4x +c
(-1,6)
6 - 4=c =2
y=-4x+2

Answer 2

y-y^1=m(x-x^1)
y-60=-4(x-(-1)
y-60=-4x-4
y=-4x+56

Answer 3

I believe the points were (-1,6) as he must have had problem with shift key when pressing 0

Answer 4

Oh thank you for clarifying, so it would be...
y-y^1=m(x-x^1)
y-6=-4(x-(-1)
y-6=-4x-4
y=-4x+2