[(y^2+y) / (3xy)] * [(3x+3) / (y^2+2y+1)]
Goodness; guide me?

Question

anonymous · Answer

$$\frac{y^2+y}{3xy} \cdot \frac{3x + 3}{y^2 + 2y + 1}$$$$=\frac{(y^2+y)(3x+3)}{3xy(y^2 + 2y + 1)}$$

I'd also look to see what you can factor out of those factors in the numerator cause some of it will cancel.

anonymous · Answer

Multiply and Expand
((3 x+3) (y^2+y))/(3 x y (y^2+2 y+1))
Now, Simplify
(x+1)/(x y+x)
(x+1)/(x(y+1))

anonymous · Answer

Also that denominator can factor nicely

anonymous · Answer

polpak; do you just distribute all that? Thank youu.

anonymous · Answer

Don't distribute yet! See what you can factor out and cancel (for example a 3 factors out of the (3x+3) and cancels with the 3 on the bottom. And a y factors out of the $(y^2 +y)$ and will cancel too

anonymous · Answer

Only distribute after you are sure that nothing else can factor and cancel.

anonymous · Answer

Alright, thanks!