Question

3a^2(a-2)(a^2+2a+4)

Answer 1

3 a^5-24 a^2

Answer 2

oh yea, and a=-7

Answer 3

\[3a^2 * (a-2) * (a^2 + 2a + 4)\]

Answer 4

a = -7

Answer 5

??

Answer 6

it says solve the equation if a=-7

Answer 7

here you use various properties of multiplication

Answer 8

yay! i love to multiply!! (well my calculator does) :P

Answer 9

Start with \[3a^2*(a-2)\]

Answer 10

just write -7 instead of a.

Answer 11

Here you will use the distributive property

Answer 12

\[3a^2 *(a-2)\] = \[3a^2 * a - 2 *3a^2\]

Answer 13

okay.

Answer 14

You don't need a calculator here

Answer 15

i understand so far.

Answer 16

So, what does this become? \[3a^2 * a - 2 *3a^2\]

Answer 17

simplify it

Answer 18

okay. so 9a^4 times a -2

Answer 19

How did you get that?

Answer 20

3 a squared times 3 a squared. i think...

Answer 21

You have \[3a^2 *a - 2*3a^2\]

Answer 22

right.

Answer 23

On the first term, \[3a^2*a\] you just do some multiplying and get \[3a^2*a=3a^3\] because \[3a^2=3*(a^2)=3*(a*a)\] and you are just mulitplying by another \[a\]

Answer 24

right. so its 3a^3-2*3a?^2

Answer 25

second term, ignore the negative for now: \[2*3a^2\] just more good ol' multiplying of \[2*3\]

Answer 26

so 6a^2?

Answer 27

so finally, you get \[(3a^3 - 6a^2)\]

Answer 28

Yes

Answer 29

You can't do anything else really to these terms, the have a raised to different values

Answer 30

\[(3a^3 - 6a^2)*(a^2+2a+4)\]

Answer 31

That is what is left of the original relation

Answer 32

i understand now! okay, thank you dpflan.

Answer 33

Now you can use the distributive property again

Answer 34

If you want to check your answer, I'll be around

Answer 35

okay, awesome! (:

Answer 36

OK, what'd you get?

Answer 37

3a^5-24a^2

Answer 38

\[(3a^3 - 6a^2)*(a^2+2a+4)\]

Answer 39

First distribute \[3a^3\] by multiplying \[(3a^3)*(a^2 + 2a +4)\]

Answer 40

that would be....

Answer 41

3a^5+12a^3-12a^3-24a^2

Answer 42

\[a^m * a^n = a^{n+m}\]

Answer 43

There should only be 3 terms for this part

Answer 44

\[(3a^3)*(a^2) + (3a^3)*2a + (3a^3)*4\]

Answer 45

3a^5+6a^2+12a^3

Answer 46

yep, missing the ^4 on the second, but you got it

Answer 47

yay!

Answer 48

now for the 2nd part: \[(6a^2)*(a^2 + 2a + 4)\]

Answer 49

We can ignore the \[-\] for now

Answer 50

6a^4+12a^3+24a^2

Answer 51

We just need to remember it at the end, or we can keep if that's less confusing

Answer 52

(-6a^2)*(a^2 + 2a + 4)

Answer 53

\[(-6a^2)*(a^2 + 2a + 4)\]

Answer 54

-6a^4-12a^3-24a^2

Answer 55

yeah, cool

Answer 56

Now combine the results of part 1 and part 2, make sure to group like terms, like the a^2's with the a^2's

Answer 57

\[(3a^5+6a^4+12a^3) + (-6a^4-12a^3-24a^2) \]

Answer 58

\[3a^5 + (6a^4 - 6a^4) + (12a^3 - 12a^2) - 24a^2\]

Answer 59

3a^5+12a^3-12a^3-24a^2

Answer 60

One more subtraction ;)

Answer 61

3a^5-24a^2

Answer 62

Bam!

Answer 63

woo-hoo!!!!! (: so happy right now!!!!! thank you sooooo much dpflan, or daniel !!!!!! (: i can't thank u enough for your help!

Answer 64

Hey, no problem, you could do, just remember to go step by step

Answer 65

i will definitely do that! gotta go now, my mom's turning off the computer, so i am about to lose the wifi! thanks again!

Answer 66

No problem, I think you got it

Answer 67

i think i do to....too....to. :)

Answer 68

too!