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find the perpendicâ€¦ - QuestionCove
OpenStudy (anonymous):

find the perpendicular bisector of the segment joining (0,2) and (3,0)

6 years ago
OpenStudy (anonymous):

first find the slope of (0,2)(3,0) which is -2/3... then flip this, so you get 3/2 as the slope of the bisector.. now what?

6 years ago
OpenStudy (anonymous):

you have done the hard work. now find the midpoint of the line segment

6 years ago
OpenStudy (anonymous):

average the coordinates you get $(\frac{3}{2},1)$is the midpoint. use point-slope formula and you are done

6 years ago
OpenStudy (anonymous):

Now find the mod points of the segment $(\frac{x_2 +x_1}{2}),(\frac{y_2 +y_1}{2})$

6 years ago
OpenStudy (anonymous):

$(\frac{x_2 +x_1}{2},\frac{y_2 +y_1}{2})$ edited

6 years ago
OpenStudy (anonymous):

yes, I know the mid points.. but.. okay so, 1= SLOPE OF WHAT (3/2) + b

6 years ago
OpenStudy (anonymous):

slope of the bisector which is.. 3/2.. which is the same as the x...?

6 years ago
OpenStudy (anonymous):

$y-y_1=m(x-x_1)$ with $x_1=\frac{3}{2},y_1=1,m=\frac{3}{2}$

6 years ago
OpenStudy (anonymous):

y=mx+b please :D

6 years ago
OpenStudy (anonymous):

$y-1=\frac{3}{2}(x-\frac{3}{2})$ etc

6 years ago
OpenStudy (anonymous):

ok fine

6 years ago
OpenStudy (anonymous):

<3

6 years ago
OpenStudy (anonymous):

$y-1=\frac{3}{2}x-\frac{9}{4}$ $y=\frac{3}{2}x-\frac{5}{4}$

6 years ago
OpenStudy (anonymous):

and you think your brain hurts!

6 years ago
OpenStudy (anonymous):

yeah Private school precalc summer packs are no joke. Neither is my teacher. Prepare for a long year :)

6 years ago