Question

find the perpendicular bisector of the segment joining (0,2) and (3,0)

Answer 1

first find the slope of (0,2)(3,0) which is -2/3... then flip this, so you get 3/2 as the slope of the bisector.. now what?

Answer 2

you have done the hard work. now find the midpoint of the line segment

Answer 3

average the coordinates you get
\[(\frac{3}{2},1)\]is the midpoint. use point-slope formula and you are done

Answer 4

Now find the mod points of the segment

\[(\frac{x_2 +x_1}{2}),(\frac{y_2 +y_1}{2})\]

Answer 5

\[(\frac{x_2 +x_1}{2},\frac{y_2 +y_1}{2})\] edited

Answer 6

yes, I know the mid points.. but.. okay so, 1= SLOPE OF WHAT (3/2) + b

Answer 7

slope of the bisector which is.. 3/2.. which is the same as the x...?

Answer 8

\[y-y_1=m(x-x_1)\] with
\[x_1=\frac{3}{2},y_1=1,m=\frac{3}{2}\]

Answer 9

y=mx+b please :D

Answer 10

\[y-1=\frac{3}{2}(x-\frac{3}{2})\] etc

Answer 11

ok fine

Answer 12

<3

Answer 13

\[y-1=\frac{3}{2}x-\frac{9}{4}\]
\[y=\frac{3}{2}x-\frac{5}{4}\]

Answer 14

and you think your brain hurts!

Answer 15

yeah Private school precalc summer packs are no joke. Neither is my teacher. Prepare for a long year :)