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If M (3,-5) is the midpoint of A (-3,1) and B(X,Y) find the coordinates of B. Please help me solve this! :)
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XM=(XA+XB)/2--->6=-3+x--->xB=9 YM=(YA+YB)/2--->2=1+yA--->yA=1 B(9;1)
Thank you! :)
The midpoint of 2 points is just the average of the coordinates
w8 i've done smth wrong
oh ok
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i get (9,-11)
YM=(YA+YB)/2---> -10=1+yB--->yB=-11
Since M is the midpoint of A, you know that your line should extend in the fourth quadrant. \[\left(\begin{matrix}x2+x1 \\ 2\end{matrix}\right), \left(\begin{matrix}y2+y1 \\ 2\end{matrix}\right)\] is your midpoint formula.
yea the answer is (9;-11)
Thank you all very much for the quick and easy help! :)
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your welcome
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