Question

void main()
{
unsigned giveit=-1;
int gotit;
printf("%u ",++giveit);
printf("%u \n",gotit=--giveit);
}

why its output is 0 65535

Answer 1

An int vary between -32 768 and 32 767 whereas an unsigned int vary between 0 and 65535.
So according to your code, gotit value is -1 BUT you are asking to display an unsigned value with your printf ("%u") so the program does the conversion automatically. If you want to display a negative value, you should write "%i" instead. :)

Answer 2

thanks