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Define integral below.
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below?
I see nothing integration of nothing respect to nothing is undefined
haha, hang on guys. :D
\[\int\limits_{}^{}\frac{x}{x+1}dx, x<-1\]
go ishaan
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go lana i havent taken so i cant answer questions
let u = x+1 du=dx integration u-1 / u = integ 1-1/u = u-lnu = x-ln(x+1)
integration by parts u= x v'= 1/x+1 du= dx v= ln(x+1) or the way lana did it
bad things are happening when I try to integrate i get I = xln(x+1) - xln(x+1) +I
all you need to integrate is \[\int ln(x+1)\]
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lol i did a mistake somewhere
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