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Mathematics 16 Online
OpenStudy (anonymous):

Define integral below.

OpenStudy (anonymous):

below?

OpenStudy (anonymous):

I see nothing integration of nothing respect to nothing is undefined

OpenStudy (anonymous):

haha, hang on guys. :D

OpenStudy (anonymous):

\[\int\limits_{}^{}\frac{x}{x+1}dx, x<-1\]

OpenStudy (anonymous):

go ishaan

OpenStudy (anonymous):

go lana i havent taken so i cant answer questions

OpenStudy (lalaly):

let u = x+1 du=dx integration u-1 / u = integ 1-1/u = u-lnu = x-ln(x+1)

OpenStudy (anonymous):

integration by parts u= x v'= 1/x+1 du= dx v= ln(x+1) or the way lana did it

OpenStudy (anonymous):

bad things are happening when I try to integrate i get I = xln(x+1) - xln(x+1) +I

OpenStudy (anonymous):

all you need to integrate is \[\int ln(x+1)\]

OpenStudy (anonymous):

lol i did a mistake somewhere

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