how about this now, another stor problem margie is certain that every time she parks in the municipal it cost her at least $2.50. if the garage charges 40 cents plus 30 cents for each half hour how long is morgie's car parked?
\[.40+.60x=2.50\]
no that is not right.
it is a penny a minute, so if you want time in minutes convert to pennies and get \[40+x=250\]
im lost
ok lets go slow
and work with pennies rather than dollars so we can ignore the stupid decimal
30 cents for half an hour. half an hour is 30 minutes, so parking is 1 cent per minute
every minute cost a penny, and you also have to pay 40 cents on top of that. so if x is the number of minutes you park, you have to pay \[x+40\] cents. for example if you park 30 minutes (half an hour) you pay 30+40=70 cents
now you know that you pay at least 250 cents. so put \[x+40=250\] and solve for x
in one step. \[x+40=250\] \[x=250-40=210\]
and so if you park for 210 minutes you pay 250 cents or $2.50
210 minutes is three and a half hours. so if you park for 3 and a half hours you pay $2.50
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