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What number in the vertex form of the equation y= 3(x – 4)^2 + 5 indicates that the parabola opens up? 2 3 4 5
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3, it is positive
When you distribute, 3 becomes the coefficient of x^2
The 3 (as pk51 said) is the coefficient of the x^2 term. It determines direction and "thinness" of the parabola. The 4 is a horizontal shift to the right of the vertex. The 5 is a vertical shift up of the vertex. The 2 tells you that it's a quadratic (and therefore has a vertex at all) :)
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