Question

-16x -1y-3/80x -4y-3 simplify

Answer 1

-16x -1y - (3/80x) -4y -3? or
(-16x -1y-3)/(80x -4y-3)

Answer 2

1st way u have it written

Answer 3

If that is the way then just combine terms getting:
42.66x-5y-6

Answer 4

i am willing to bet this is
\[\frac{-16x^{-1}y^{-3}}{80x^{-4}y^{-3}}\] because i saw this problem today already

Answer 5

I think you're right, it looks wrong

Answer 6

cancel the -16 and the 80 leaves -5 in the denominator. the
\[y^{-3}\] cancel as well. this leaves
\[\frac{x^{-1}}{-5x^{-4}}\] now bring up the
\[x^{-4}\] into the numerator to get
\[\frac{x^{-1}x^4}{-5}\] ad the exponents to get
\[-\frac{x^3}{5}\]

Answer 7

yeah i saw this once already

Answer 8

Hopefully bradley0516 will verify.

Answer 9

yes thats the way it was written but no one had responded so I reposted it again

Answer 10

Looks like you got an answer now.