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ose is paying for a $6meal using bills in his wallet. He has four 1$ bills, three 5$ bills, and two10$ bills. If he selects two bills at random, one at a time from his wallet, what is the probability that he will choose a 1$ bill and a 5$ bill to pay for the meal? Show your work.
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The guy has a total of 9 bills: 4 bills of $1 3 bills of $5 2 bills of $10 The probability of choosing any of those is as follows: 4/9 for $1 3/9 for $5 2/9 for $10 The probability that he will choose a $1 bill and a $5 bill is as follows: 4/9 * 3/8 = 1/6 I suck at statistics though. You should wait for someone else to corroborate this.
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