Question

A plane landing on a small tropical island has
just 56 m of runway on which to stop.
If its initial speed is 62 m/s, what is the
maximum acceleration of the plane during
landing, assuming it to be constant?
Answer in m/s^2


How long does it take for the plane to stop
with this acceleration?
Answer in units of s

Answer 1

what is the smallest acceleration required to stop

Answer 2

Ok let's work on this one together

Answer 3

We're assuming it is able to stop, for the smallest possible acceleration you will use the entire runway of 56 m, does that make sense?

Answer 4

the formula i was using is v^2=v(initial)^2 +2a(x-x(initial))
and, yeah, that makes sense

Answer 5

So ok, you have final velocity of 0, since you stopped, and initial velocity of 62, you also have distance travelled of 56m, I would recommend using this formula:

Vf^2 = Vi^2 + 2ad

Where Vf is final velocity, Vi is initial velocity, a is acceleration (you're solving for this) and d is the distance travelled

Answer 6

So let's substitute your numbers into the formula:

(0)^2 = (62) ^2 + 2*(a)*(56)

From this I get a = -34.32 m/s^2

Answer 7

awesome, i can see where i went wrong. thanks

Answer 8

i can finish the next part

Answer 9

There are really just 3 formulas for you to know for this topic:
Vf^2 = Vi^2 + 2ad
Vf = Vi + at
d = Vi*t + 0.5*a*t^2

Answer 10

k. thanks

Answer 11

How long does it take for the plane to stop
with this acceleration?
Answer in units of s