Question

center and radius of a circle

x^2-10x+y^2=8

Answer 1

you need to "complete the square" to write it as
\[(x-h)^2+(y-k)^2=r^2\] and then read off the solution as
center
\[(h,k)\] radius
\[r\]

Answer 2

(x-5)^2-25+y^2==8
(x-5)+y^2=33
(5,0) center
radius sqrt(33)

Answer 3

as follows
\[(x-5)^2+y^2=8+5^2\]
\[(x-5)^2+y^2=33\]
so center is
\[(5,0)\]
\[r=\sqrt{33}\]

Answer 4

what jahtoday said!

Answer 5

yay!