Question

https://courses.vlacs.org/vlacontent/algebra2_v10_gs//assessments-xml/res0055/4_006_30.gif%22

Help? I keep coming to 15/12, but that isn't an option, so it can't be right :/ I find a common denominator, then subtract the numerators ... Where am I going wrong?

Answer 1

what are the choices

Answer 2

would it help to look at the problem as
\[x^(3/4) * x^-1/6\]

Answer 3

Choices are:
https://courses.vlacs.org/vlacontent/algebra2_v10_gs//assessments-xml/res0055/4_006_12.gif%22
https://courses.vlacs.org/vlacontent/algebra2_v10_gs//assessments-xml/res0055/4_006_13.gif%22
https://courses.vlacs.org/vlacontent/algebra2_v10_gs//assessments-xml/res0055/4_006_14.gif%22
https://courses.vlacs.org/vlacontent/algebra2_v10_gs//assessments-xml/res0055/4_006_15.gif%22

And they're being divided, not multiplied, right? O.o

Answer 4

wait

Answer 5

see as we know that (a^b)/(a^c) = a^(b-c)
hence here (x^3/4)/(x^1/6) = x^(3/4 - 1/6)
= x^(14/24)
= x^(7/12)

Answer 6

I figured it out, actually, haha. But thanks! I'll give you a medal anyhow :] I feel so silly now.

Answer 7

(x^((3)/(4)))/(x^((1)/(6)))

Reduce the exponents of x by subtracting the denominator exponents from the numerator exponents.
x^(((3)/(4))-((1)/(6)))

Multiply -1 by each term inside the parentheses.
x^((3)/(4)-(1)/(6))

Combine -(1)/(6)+(3)/(4) into a single expression by finding the least common denominator (LCD). The LCD of -(1)/(6)+(3)/(4) is 12.
x^((7)/(12))

Answer 8

And I feel really bad about making you do all that work for nothing. Sorry! ;/

Answer 9

ok no problem and thanks for giving me medal any more questions ?

Answer 10

I have one :] Want me to post it in another thread so I can medal you for it, too? It's a different problem altogether.

Answer 11

u can post it there also if u think so . but please do it fast as i have to go some where after 1/2 hour . post it . i would try to solve it

Answer 12

https://courses.vlacs.org/vlacontent/algebra2_v10_gs//assessments-xml/res0055/4_003_01.gif%22

I need help with that. I keep getting the wrong answer.

Answer 13

And I've solved a TON of those and gotten them right every time, so I have no idea why I'm struggling with this one.

Answer 14

ok can i know how u went to these questions ?

Answer 15

How I went to them? What do you mean went?

Answer 16

(2+5~(3))(7-~(3))

Multiply each term in the first group by each term in the second group using the FOIL method. FOIL stands for First Outer Inner Last, and is a method of multiplying two binomials. First, multiply the first two terms in each binomial group. Next, multiply the outer terms in each group, followed by the inner terms. Finally, multiply the last two terms in each group.
(2*7+2*-~(3)+5~(3)*7+5~(3)*-~(3))

Simplify the FOIL expression by multiplying and combining all like terms.
(14+33~(3)-5~(3)^(2))

Remove the parentheses around the expression 14+33~(3)-5~(3)^(2).
14+33~(3)-5~(3)^(2)

Raising a square root to the square power results in the expression inside the root.
14+33~(3)-5(3)

Multiply -5 by each term inside the parentheses.
14+33~(3)-15

Subtract 15 from 14 to get -1.
-1+33~(3)


here ~ this means sqrt sign . that is \[\sqrt{?}\]

Answer 17

got it !!!!!!!!!!!!

Answer 18

It's from a review/practice test -- that's why it's so important I understand these, haha.

Answer 19

and i meant that how r u viewing these questions

Answer 20

it means u have got it understood ?

Answer 21

Yep, I understood. Thanks!

Answer 22

my pleasure , any more questions ?

Answer 23

Nope :] Thanks so much! You're awesome.

Answer 24

thanks very much any more questions u can ask me to my email id ( kushashwaravishrimali@gmail.com )