Let ABC be a triangle in which AB=AC and I be its in-centre . Suppose BC = AB + AI . find angle BAC
This is a pig of a question, it looks like something might possibly drop out if I can convert everything to r and look at Tan theta/2. Do u actually have a solution (if u do, don't tell me, just tell me that u have one).
yes i have one
angle ABC is 90 degree right?
no hint abc is a right triangle but angle b is not 90
Now we know the answer, I still haven't managed to demonstrate it though. I got an equation for theta saying there is no real solutions....:-(
Can't see the wood for the trees....see diagram. The 2 little triangles containing x (theta 2) are congruent) so d = r and Sin x = Cos x ie 45 degrees so BAC is 90.
if u want i can give u the solution
Above is a solution.
yaa didnt see it clearly sorry
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