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2x^2+2y+10. solve for y.
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2x^2 + 2 y+10 = 0
no, thts wrong.
2x^2+10=-2y
y= -x^2 -10
nope
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-x^2-5
subtract 2y from both sides, then divide by -2 you end up with y=-x^2-10
+10/-2 = -10?
that's right should be -5..thanks!
whoz right?
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who wants a medal?
lol
meee
to solve 2x^2+2y+10 = 0; => x^2+y+5=0; =>y=-(x^2+5); how about that....
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