Ok how do you go about solving these types of problems where there are more then so many unknowns you have to solve for they have me stumped? A car travels along a straight line at a constant speed of
60.0 mi/h for a distance d and then another distance d in
the same direction at another constant speed. The average
velocity for the entire trip is 30.0 mi/h. (a) What is the constant
speed with which the car moved during the second
distance d?

Question

preetha · Answer

As in any problems start with listing the information you have and then the relationships you know.

anonymous · Answer

I know the final velocity for the trip is 30mph and the intial velocity is 60mph. And I have to find the distance that it travels during second leg of trip but I nothing more.

anonymous · Answer

according to the question, the average velocity is 30 mi/h, so the final velocity of the velocity on the last leg of the trip would be... 0 mi/h. That is the on way the average velocity can be half of the original velocity. As for the "d" conundrum, distance can't be found without TIME.
Average velocity equation:$$(v _{1}+v _{2})/2$$