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OpenStudy (anonymous):
Which expression is the simplified form of the square root of z^7 ?
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OpenStudy (anonymous):
(z^7)^(1/2)=
z^(7/2)
OpenStudy (anonymous):
it has to be one of these?
z square root of z^3
z^2 square root of z
z^3 square root of z
z^3 square root of z^2
OpenStudy (phi):
Here's a hint
\[z^{7/2}=z^{\frac{6}{2}+\frac{1}{2}}= z^{\frac{6}{2}}z^{\frac{1}{2}}\]
OpenStudy (anonymous):
is it the second one cause thats what i got the first time i did it.
OpenStudy (phi):
Look at the exponents in my hint. 6/2 =3 and 1/2 means square root.
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OpenStudy (anonymous):
okay i am still a little cunfused but i think its the last one?
OpenStudy (anonymous):
try again
OpenStudy (phi):
\[z^{\frac{6}{2}}z^{\frac{1}{2}}= z^{3}z^{1/2}\]
by definition, \[z^{1/2}= \sqrt{z}\]
OpenStudy (anonymous):
okays so the third one?
OpenStudy (phi):
Yes. Can you figure out why you are confused?
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OpenStudy (anonymous):
yeah sorry this question just confused me more than the others thanks your your help! :)
OpenStudy (phi):
practice makes perfect.
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