Question

Bob has $2.90 in pennies, nickels and dimes. He has the same number of pennies and nickels. If the number of dimes is 5 more than the number of nickels, how many of each type of oin does he have?

Answer 1

thanks guys for helping

Answer 2

imran's got it

Answer 3

wait souldnt it be like
.05n+.1d+0.01p=2.90

Answer 4

soooo wat next

Answer 5

.05n+.1d+.001p=2.90
n=p
d=n+5

.05n+.1(n+5)+.01(n)=2.90

Answer 6

.0001? think it's just .001

Answer 7

n=15

Answer 8

yess shouldn't it be that i got 15=x which equals 15 nickels and 15 pennies and 20 dimse

Answer 9

Wait-I mean.01

Answer 10

im confused

Answer 11

which equates to the problem because i says p=n and d=n+5

Answer 12

n=15 , p=15, d=20

Answer 13

how do u get that answer

Answer 14

.05n+.1(n+5)+.01(n)=2.90
0.16 n+0.5=2.90
0.16n=2.40
n=2.40/0.16

Answer 15

n=15

Answer 16

n=p
so p=15 as well

Answer 17

d=n+5
d=20

Answer 18

thank you