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Solve logx + 5 36 = 2 Please help me understand what "log" means and what it does to the equation?
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\[\log_{x+5}(36)=2\] means in equivalent exponential form that \[(x+5)^2=36\] now solve for x
you change \[\log_b(x)=y\] to \[b^y=x\] as equivalent exponential form
now it is easy enough to solve. write \[x+5=6\] or \[x+5=-6\] so \[x=1\] or \[x=-11\] but the base cannot be negative so it is \[x=6\]
sorry i mean \[x=1\] not 6
\[x=1\] so \[x+5=6\] is the base
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But if it could be negative would it be -6?
or 6?
Wait can it ever be negative?
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