Question

this
3x+2y=-5
4x-3y=16

Answer 1

ok multiply the first equation by 3 straight across to get
\[9x+6y=-15\]

Answer 2

then multiply the second equation by 2 to get
\[8x-6y=32\]

Answer 3

add them and the y's will add to zero, so they drop out of the resulting equation
\[9x+6y=-15\]
\[8x-6y=32\]
\[17x=17\] so now you know that
\[x=1\]

Answer 4

now that you know x is 1 you can replace x by 1 in either equation to get y. i choose the first one
\[3\times 1+2y=-5\]
\[3+2y=-5\]
\[2y=-8\]
\[y=-4\] so your answer is
\[x=1,y=-4\]