Find the function f(x) which has the following Laplace transform:

1/(s-1)^2

...Is it (e^t)^2?

Question

Find the function f(x) which has the following Laplace transform:

1/(s-1)^2

...Is it (e^t)^2?

anonymous · Answer

Oooh, I figured out how to make Wolfram do these:-) (cheating I know) http://www.wolframalpha.com/input/?i=InverseLaplaceTransform+1%2F%28s-1%29^2

anonymous · Answer

Is it right?

anonymous · Answer

The table on Wikipedia gives "nth power with frequency shift" for 1/(s+alpha)^(n+1)

What's that all about?

anonymous · Answer

wow wolfram rules!

phi · Answer

I don't know if this will make any sense, but ….
In signal processing, we can model a signal as exp(i w t), 
if we multiply by exp( i w0 t), w0 a constant,
we get exp(i (w + w0) t)  which is the original signal shifted in frequency.

This property holds for a general f(t) function: exp(i w0 t)*f(t) shifts the signal in frequency.

anonymous · Answer

Thanks, I kind of get that, let me do a bit of reading..

anonymous · Answer

Oh, I see, the u(t) is Heaviside step (teach me to read a bit before jumping in with both feet...)