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If a circle is circumscribed around a square and we know the radius of the circle how do we find the are of the square?
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A = pi r^2
I know how to find the area of the circle, but I need the area of the square inside
the diagonal of the square is equal to the diameter of the circle
use the pythag thrm to find the length of the sides
s^2 + s^2 = diameter^2 2s^2 = d^2 d^2 s^2 = --- 2 d^2 s = sqrt( --- ) 2 s = d/sqrt(2)
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or simply stop at s^2 since the area of a square is s*s :)
Thanks so much! Cheers
Something to ponder...
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