Mathematics
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OpenStudy (anonymous):
x+square root of x=12
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OpenStudy (anonymous):
That's not even the right question Kushash..
OpenStudy (anonymous):
\[x+\sqrt{x}=12\]
OpenStudy (anonymous):
\[\sqrt{x}=12-x=>(\sqrt{x})^2=(12-x)^2=>x=144-24x+x^2\]
OpenStudy (anonymous):
1 subtract x from both side
2 square both side
OpenStudy (anonymous):
my thingy got cut off
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OpenStudy (anonymous):
Multiple lines is easier to read.
OpenStudy (anonymous):
do i factor 0=x^2-24x+144
OpenStudy (anonymous):
yes,
OpenStudy (anonymous):
what add up to -24 and multiplies to 144?
OpenStudy (anonymous):
kushash.. That is not the right problem. Seriously. Stop spamming.
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OpenStudy (anonymous):
kushashwa is half right. x can be 9. he put the answer for root(x).
OpenStudy (anonymous):
i think it should be -25x in the middle
OpenStudy (anonymous):
thats what i thought monkey
OpenStudy (anonymous):
because you still have that other x on the left side
OpenStudy (anonymous):
You can either factor it, or use the quadratic equation.
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OpenStudy (anonymous):
right and if you subract that x on both sides
you have -24x-x
OpenStudy (anonymous):
in which case it is 0=x^2-25x+144 which makes it more difficult
OpenStudy (anonymous):
x^2-24x-x+144=0
OpenStudy (anonymous):
so then i should use the quadratic equation to solve?
OpenStudy (anonymous):
you can do factoring
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OpenStudy (anonymous):
(x-9)(x-16)=0
OpenStudy (anonymous):
x = 9,16
OpenStudy (anonymous):
you guys are awesome thank you
OpenStudy (anonymous):
If it is something you cannot factor easily, using the quadratic formula always works. Even if it's factorable, sometimes you can't figure it out.