Question

Can someone help me with this problem? I don't even know what it's called to look it up on a math website. 5x^3-2 if x<-6

Answer 1

umm do u want it graphed

Answer 2

or solved?

Answer 3

cause i dont know what part to solve

Answer 4

This is a math packet I'm supposed to do as an incoming junior in a precalculus class. The only instructions are to how al my work on a separate sheet of paper and consult purplemath.com if help is needed

Answer 5

i know the graph 5(x^3)-2 where u restrict the domain to x<-6

Answer 6

well you could substitute in -6 to give a limit to the function
-> 5*(-6)^3 -2 = -1082
so f(x) < -1082 for x<-6

Answer 7

yh can restrict y values with it as well

Answer 8

i recommend graphing it

Answer 9

the answer sheet says the answer is 106

Answer 10

but here's the whole problem:

let f(x) = [ 5x^3 -2 if x <-6
3x^2 - 2 if -6 <_ x <7
7+ 2x if x _> 7

find f(-6), f(0), f(6), f(7), f(10)

Answer 11

http://www.purplemath.com/modules/ineqsolv.htm

Answer 12

its is a piece wise function

Answer 13

u plug in f(-6) in second equation 3(-6)^2-2 because x is between -6 and 7=106
u plug in f(0) in second equation 3(0)^2-2 because x is between -6 and 7=0
u plug in f(7) in third equation 7+2(7) because x is = 7
u plug in f(10) in third equation 7+2(10) because x is more than 7

Answer 14

answers are 106

Answer 15

-2

Answer 16

21

Answer 17

27

Answer 18

THANK YOU SO MUCH!!!!