Question

Square GHIJ is inscribed in circle K. If GH = 46, calculate the area of the three shaded segments formed by the circle and square.

Answer 1

i can do this

Answer 2

lalaly i need u!!!haha.....someone please help

Answer 3

wouldnt it be 4 regions left when u put a square

Answer 4

no i gotta go - see you guys tomorrow

Answer 5

well the radius if 23sqrt(2) because it forms half the diagonal of the square
Area of square = 46^2
Area of circle = pi*(23sqrt(2))^2 = 2*pi*23^2

Answer 6

radius is 23sqrt(2)

Answer 7

1058 pie -48^2

Answer 8

1019.81

Answer 9

It has 3 of 4 sides shaded and im trying to calculate the area of the 3 that are shaded.

Answer 10

764.86

Answer 11

JH is diameter JH=HI = 46 ... by pythagorus
so JH^2 = 46^2 + 46^2
JH = 65.053
Radius = diameter/2 = 32.526
Area of circle = pi*r^2 = 3.14*1058=3322.12
subtractin area of square frm area of circle
Area of 4Parts = 1206.12
area of 1 Part = 1206/4 = 301.15
area of 3 Parts = 301.15*3 = 904.59

Answer 12

ok then take
(AreaCircle - AreaSquare)*(3/4)

Answer 13

lalay got it!!!!.....you are soo smart...thx for helping everybody....i still have a few more;)

Answer 14

i get 905.85, lala you could be off due to rounding