Question

a rectangle has length triple the side of a square and width two units less than the side of the square. if the two areas are equal, what are the square's dimensions?

Answer 1

the area of the square is x^2
The rectangle has an area of : 3x * (x-2)
The two areas are the same so: x^2=3x^2-6x
Thus: -2x^2=-6x
Divide both sides by -2 and get: x^2=3x, now divide both sides by x and get:
x=3, thus the square has sides of lenght 3.

Answer 2

thank you very much!