help with this question: solve with elimination. 6x+y=-10 3x-y=3
can you see that if you add these toghether the y variable will cancel out?
yes i did that but after that is confusing
Well, it leaves other stuff - try to add them together.
well after adding i get, and hopefully you get: 9x=-7
Which means that the x is something, and when you know x - voila!
wait i eliminated the y's then i got: 6x=-12 and 3x=3
how did you get that? if you add 6x+3x you get 9x right?
you add the 6x and the 3x and the -12 and the 3?
You didn't eliminate them, you added them together - do that with the rest as well:)
where is the negative 12 coming from?
6x+y=-10 3x-y=3 + ------------- 9x=-7
oh sorry the -10 was originally a -12, i typed it out wrong
okay anyway this is what you get: 6x+y=-12 3x-y=3 + ------------- 9x=-9
so it would be: 9x=-9, right
so x=-1
correct
now, just plug that into any of the equations and solve for y
i get 2
but the answer key says it should be -1 and -6
How do you get 2 then?
x=-1 which is correct.
i dont know
yes but i need a -6 too
Just write the equations again. Then you write -1 where all the x-es are (its good to use () ). Then solve it as a regular problem.
ok, thanks i got it
You can use whichever problem you want, but one is usually easier to solve. Woohoo!:D
Its also smart to check if both problems add up once you've got both of them.
thanks
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