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Mathematics 21 Online
OpenStudy (anonymous):

Looking for answers to check (Integral in comment)

OpenStudy (anonymous):

\[\int\limits_{?}^{?}dx/x^2\sqrt{4-x^2}\]

OpenStudy (anonymous):

anyone there? lol? i got \[-\sqrt{4-x^2}/2x+c\]

OpenStudy (anonymous):

Hold on

OpenStudy (anonymous):

still working lol?

OpenStudy (anonymous):

tricky one, I think

OpenStudy (anonymous):

still working lol?

OpenStudy (anonymous):

if it helps to tell you it is a trig substitution i just need to find my mistake if i was wrong

OpenStudy (anonymous):

still working lol?

OpenStudy (anonymous):

the next one is going to be a trig sub too that i'm posting

OpenStudy (anonymous):

I tried that, didn't help

OpenStudy (anonymous):

still working lol?

OpenStudy (anonymous):

trig sub? let x = 2sin(theta)

OpenStudy (anonymous):

still working lol?

OpenStudy (anonymous):

solve for dx and find a substitution for the sqroot

OpenStudy (anonymous):

yeah but 1/x^2 is sticking out

OpenStudy (anonymous):

still working lol?

OpenStudy (anonymous):

i ended up getting 2cos(theta)/4sin^2(theta)cos(theta)

OpenStudy (anonymous):

still working lol?

OpenStudy (anonymous):

yeah but you can simly replace x^2 with your substitution of x, right? so in other words you get 4sin^2(theta)

OpenStudy (anonymous):

Oh I see

OpenStudy (anonymous):

i'm going to post another in a sec if you want to try that one also to check my answer. I use this as a check because my teacher didn't give us the answers

OpenStudy (anonymous):

ok sure

OpenStudy (anonymous):

the answer is \[-\frac{\sqrt{4-x^2}}{4 x}\]

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