Question

factor x^3-3x^2-4x+12 please show work. im trying to remember how this is done

Answer 1

grouping so you have (^3 - 3x^2) and (-4x+12) they have common factors

Answer 2

x^\[x^2(x-3)-4(x-3)\]

Answer 3

\[(x^2-4)(x-3)\]

Answer 4

no it's not multipy yours out and you wont the beginning equation

Answer 5

\[(x^2*x)+(x^2*-3) + (-4*x)+(-4*-3) = x^3 - 3x^2 -4x+12\]