Question

(Please, show how you got your answer, I'm not sure how to do this...)

Segment ST is congruent to segment SR and QR is congruent to segment SR.

___ ___
QR=x+4 and ST=5(3x-2)

x+4=5(3x-2)
-4 -4
x= 5(3x-6)

Now.....what do I do now?

Answer 1

you want to multiply out (or distribute) that 5 on the right hand side of the equation:
\[5(3x-6) = 5*3x-5*6 = 15x-30\]

Answer 2

5(3x-6)=5(3x)-5(6)=...something
15x-30=x !!!!!
x=15x-30
-15x -15x?

Answer 3

right. you are on the right track :)

Answer 4

So...
-14x=-30
---- ---
-14 -14?
x=15/7?

Answer 5

? Mahalo nui loa for the medal.... :)

Answer 6

ack, i didnt notice what you had done in the very beginning was incorrect >.< by bad.

Lets start from the beginning.

Answer 7

Really? Ok. Let's do this!!!!

Answer 8

you have:
\[x+4 = 5(3x-2)\]
From there, you need to multiply that 5 out first before you subtract 4 from both sides of the equation.

Answer 9

x+4=5(3x-2)...
So I divide 5 out of the equation first?

Answer 10

you have to multiply it out, like this:
\[5(3x-2) = 5*3x-5*2 = 15x-10\]

Answer 11

15x-10=x+4
Now do I subtract 5?

Answer 12

I mean 15x...

Answer 13

you can do that if you want. That would leave us with:

15x - 10 = x + 4
-15x -15x
-10 = -14x+4

Answer 14

So now we are at:
-10 = -14x + 4

what should we do next?

Answer 15

Get rid of the four....
-14=-14x

Answer 16

thats correct. now one more move....

Answer 17

-14/-14=-14x/-14
1? x=1?

Answer 18

yes, that answer looks a lot nicer than what we had before lol.

Answer 19

:) Ok. Thank you for your help. I appreciate it! x)

Answer 20

no problem :)