Question

Simplify 6 4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4.

Answer 1

64*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4.
or
6*4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4 ?

Answer 2

lol yes i find this confusin also lol

Answer 3

the 6 and the 4 are separate. it's 6 4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4. or 6*4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4
by the asteric i mean that the number before it is a small raised number.

Answer 4

so the numers asterick are cube/4th roots yada yada?

Answer 5

yup.

Answer 6

so in other words it is this

\[6\sqrt[4]{4}\]

Answer 7

as the first part?

Answer 8

exactly!

Answer 9

alright i'll equate it out for nick so he can make sure i'm sure he's got hte right answer

\[6\sqrt[4]{4}-8\sqrt[3]{4}+2\sqrt[3]{4}-3\sqrt[3]{4}\]

Answer 10

6*4√4 - 7 *3√4 + 2 *3√4 - 3 *3√4
3√4(6*√4-7+2-3)
3√4(6*√4-8)

Answer 11

is that correct?

Answer 12

yes. (:

Answer 13

nick's answer is right or the way i showed it/

Answer 14

out u wrote 8 instead of 7

Answer 15

and 95 girl i am right i just simplified it

Answer 16

i took 3√4 common

Answer 17

out u do it too y will get the same one wht i got

Answer 18

it's correct it just looks so weird when you use a check to show sqroot i see it as all under the root

Answer 19

its correct so i deserve a medal too bro

Answer 20

lol