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can someone show me how to find the zeros... f(x) =x^3+4x^2+4x. FIND the zeros of f.
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set it = 0 so you can factoooorrrr
and you can factor out an x from the get go!
0= x(x²+4x-4)
right x(x^2+4x+4)=0 x(x+2)^2=0
0=x(x +2) (x-2) x = 0 x = 2 x= -2 these are the zeros.
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x=0, and x+2=0 is x=-2
f is written just beside x.
lol yes, correct saifooooo.
^im confused... >.<
are u?
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NEVER MIND. got it! haha
yayyyyyyyyyyy
yo
sup
im not so good at graphs..so.. f(x)=1-3^x the graph of f is reflected over the line y=x. what is the name of function of the new graph?
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