i just cant wrap my head around it
factor
x^2-10x+21
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OpenStudy (anonymous):
7 and 3!
jimthompson5910 (jim_thompson5910):
Find two numbers that multiply to 21 AND add to -10: These numbers are -7 and -3
x^2-10x+21
x^2-7x-3x+21
x(x-7)-3(x-7)
(x-7)(x-3)
So x^2-10x+21 = (x-7)(x-3)
OpenStudy (anonymous):
lol my first thoughts were 7 and 3 too XD
OpenStudy (saifoo.khan):
\[\Huge (x-3)(x-7)\]
OpenStudy (anonymous):
ohhhhhhhh!!!!!! two negatives make a positive thanks guys
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OpenStudy (anonymous):
what is that cool way that they teach nowadays where the leading and last coefficient = yada yada... i never use that way
OpenStudy (anonymous):
x^2-10x+21
x^2-7x-3x+21
(x-7)(x-3)
OpenStudy (anonymous):
leading and last are only for problems with a coefficent on the first x
OpenStudy (anonymous):
oh hahaha i never use it so i wouldn't know haha
OpenStudy (anonymous):
like 7x^2+5x+30 or something. factors of 7 and factors of 30
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OpenStudy (anonymous):
4y^2_49????
OpenStudy (anonymous):
*-
jimthompson5910 (jim_thompson5910):
4y^2-49 = (2y+7)(2y-7) using the difference of squares rule.