Question

solve x^4=1 for x
should be 4 solutions. lol

Answer 1

x=1, x=-1

Answer 2

i guess 2 only

Answer 3

(x+1)(x-1)(x+1)(x-1)?

Answer 4

no x=1 and -1 are the only solution.

Answer 5

yes the thing you did is right

Answer 6

that is 0 so only x=1 or x=-1 done

Answer 7

so am i right???

Answer 8

lol yea!! don't doubt that nick! you are

Answer 9

\[\Huge \begin{array}l\color{red}{\text{w}}\color{orange}{\text{h}}\color{#9c9a2e}{\text{o}}\color{green}{\text{ }}\color{blue}{\text{i}}\color{purple}{\text{s}}\color{purple}{\text{ }}\color{red}{\text{r}}\color{orange}{\text{i}}\color{#9c9a2e}{\text{g}}\color{green}{\text{h}}\color{blue}{\text{t}}\color{purple}{\text{?}}\color{purple}{\text{?}}\color{red}{\text{}}\end{array}\]

Answer 10

-1and -1 is 1answer...so only 2solution exist...

Answer 11

x^4=1

x^4-1=0

(x^2)^2-1^2=0

(x^2-1)(x^2+1)=0

(x-1)(x+1)(x^2+1)=0

x-1=0, x+1=0, or x^2+1=0

x=1, x=-1, or x^2=-1

x=1, x=-1, x=sqrt(-1) or x=-sqrt(-1)

x=1, x=-1, x=i or x=i

Answer 12

my teacher is VERY smart. I think there are four lol.

Answer 13

oops meant to say x=1, x=-1, x=i or x=-i

Answer 14

yes there are 4 and those are the solutions

Answer 15

rule of thumb: degree of polynomial = number of solutions

Answer 16

of course, I'm talking about complex solutions

Answer 17

there is a reason I'm a fan of you jim.

Answer 18

wait could I say (x²-1)(x²+1) = 0
and then x²=±1 and x²=±i?

Answer 19

I think you mean x=±1 or x=±i, which is the shorthand for saying x=1, x=-1, x=i or x=-i

Answer 20

oo, yeah, woops. lol

Answer 21

Remember, the plus/minus only comes from taking the square root of both sides.

Answer 22

even if one side is -?

Answer 23

what do you mean

Answer 24

well x²= -1
does that mean x=±1?

Answer 25

no it means +-i

Answer 26

no, taking the square root of both sides means that

x^2=-1


x=sqrt(-1) or x=-sqrt(-1)


x=i or x=-i


since i = sqrt(-1)

Answer 27

oh, yeah that was my mistake but you still answered the intent of my question lol

Answer 28

that's good that you're asking though

Answer 29

So you wanted complex roots to?
nice job jim