Question

One leg of the right triangle is 20 centimeter and the hypotenuse is 10 centimeter longer than the other leg. Find the lengths of the unknown sides.

Answer 1

pythagoras for this one
put the length of the "other side" as x, then hypotenuse is
\[x+10\]
two legs are 20 and x
pythagoras says
\[20^2+x^2=(10+x)^2\] and now you have a nice equation to solve

Answer 2

how?? please give me the exact soultion

Answer 3

it looks like a quadratic equation but it is not.
square and get
\[400+x^2=100+20x+x^2\] i bet you can go from there right?

Answer 4

it's not hard just a lot of leg work

Answer 5

welcome to "real" math...enjoy

Answer 6

its too hard for me..please give the exact solution...thanks

Answer 7

actually at this stage rather little leg work. solve in three steps
1) subtract x^2 from both sides
2) subtract 100 from both sides
3) divide both sides by 20

Answer 8

i mean in terms of you have to actually write it down and solve it...can't just look at it anymore

Answer 9

@leninyr i am sure it is not too hard for you now. follow the 3 steps and you will get it

Answer 10

leinyr...do your own homework....he's helped you a ton

Answer 11

oh yes of course! at some point you actually have to compute something. no getting around that.