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Mathematics 10 Online
OpenStudy (anonymous):

Polpak, please help me, I need help big time!

OpenStudy (anonymous):

/: Help ?

OpenStudy (anonymous):

yes..whats your question?

OpenStudy (anonymous):

I have to find the slope and yintecept of two segments, and I need to show inequalites that will show the same soordinates

OpenStudy (anonymous):

Coordanates

OpenStudy (anonymous):

Interesting...so can you give the equations of the two segments?

OpenStudy (anonymous):

Or was there any other info given?

OpenStudy (anonymous):

I have to coordniates

OpenStudy (anonymous):

the*

OpenStudy (dumbcow):

slope (m) \[m = \frac{y2-y1}{x2-x1}\] y-intercept (b) \[y = mx +b\]

OpenStudy (anonymous):

Yeah dumbcow is right use the slope formula to figure out slope of the line with the coordinates given

OpenStudy (dumbcow):

Use points as x,y values point 1: (x1,y1) point2: (x2,y2)

OpenStudy (anonymous):

AB (0,5) (4,5) BC (4,5) (2,3) CA (2,3) (0,5) I would but I dont know how to do that

OpenStudy (dumbcow):

wait, this makes a triangle what is the question again?

OpenStudy (anonymous):

I have to have inequalties that define each segment

OpenStudy (dumbcow):

oh ok yeah you have to put each segment in slope intercept form y=mx +b then determine if the inside of triangle is above or below the line

OpenStudy (dumbcow):

you should first draw out the segments so you can see the triangle

OpenStudy (anonymous):

I did , I have it already....

OpenStudy (dumbcow):

ok i'll do the 1st one for you

OpenStudy (dumbcow):

AB (0,5), (4,5) point 1 (0,5) --> x1 = 0, y1 = 5 point 2: (4,5) --> x2 = 4, y2 = 5 \[m = \frac{y2-y1}{x2-x1} = \frac{5-5}{4-0} = 0\] y = mx + b Using point 1, x =0, y=5 5 = (0)(0) + b 5 = b y = 5 triangle is below this line so make inequality less than or equal y <= 5

OpenStudy (dumbcow):

do the other 2 in the same way

OpenStudy (anonymous):

dumbcow when I graphed it I got the triangle directly on the line y = 5

OpenStudy (anonymous):

Soo... (4,5) (2,3) Pouint 1 (4,5) --> x1 = 4 y1 = 5 Point 2 (2,3) ->> x2= 2 y2= 3 \[m = \left(\begin{matrix}y2-y1 \\ m2-m1\end{matrix}\right) ---\left(\begin{matrix}3-5\\ 2-4\end{matrix}\right)\]

OpenStudy (dumbcow):

yes the side of the triangle is on the line y=5 but the area inside triangle can be described only if y<=5

OpenStudy (anonymous):

I get it know

OpenStudy (dumbcow):

good so far

OpenStudy (anonymous):

This is what I got

OpenStudy (anonymous):

And now Im lost on what to do

OpenStudy (anonymous):

And now Im lost on what to do

OpenStudy (dumbcow):

keep computing m 3-5 = -2 2-4 = -2 then divide

OpenStudy (anonymous):

0?

OpenStudy (dumbcow):

-2/-2 = ?

OpenStudy (anonymous):

1

OpenStudy (dumbcow):

good so the slope = 1 now use equation y=mx+b pick a point to use for x,y values and m=1

OpenStudy (anonymous):

How do I uhm .. Do the equation for the inequality?

OpenStudy (dumbcow):

solve for b first

OpenStudy (anonymous):

??????

OpenStudy (dumbcow):

we have write the line segment in slope-intercept form slope-intercept form is y = mx +b m =slope b = y-intercept we solved for slope and got m=1 now solve for b lets use point (2,3) -> x=2,y=3 3 = (1)(2) + b can you solve for b now?

OpenStudy (anonymous):

Uhm.. 2?

OpenStudy (anonymous):

1!!!!!

OpenStudy (anonymous):

1!!!!!

OpenStudy (dumbcow):

haha yes 3-2 = 1 good job ok so now we have equation y = x+1 is triangle above or below this line

OpenStudy (anonymous):

Above?

OpenStudy (dumbcow):

yep so what should the inequality be?

OpenStudy (anonymous):

y >= x+1

OpenStudy (dumbcow):

perfect now 1 more to go

OpenStudy (anonymous):

Help me through it?

OpenStudy (anonymous):

Help me through it?

OpenStudy (dumbcow):

ok you find the slope and we'll go from there

OpenStudy (anonymous):

Hold on, Im trying to write what I have so far

OpenStudy (anonymous):

Hold on, Im trying to write what I have so far

OpenStudy (anonymous):

Point 1: (2,3) --> x1= 2 y1= 3 Point 2: (4,5) ---> x2= 2 y2= 5

OpenStudy (dumbcow):

wait we just did this one (2,3) (0,5)

OpenStudy (anonymous):

Noo we did 4,5 2,3

OpenStudy (anonymous):

Noo we did 4,5 2,3

OpenStudy (anonymous):

Nvmd ... Okay

OpenStudy (anonymous):

m= y2-y1/ x2-x1 ----> 5-3/0-2

OpenStudy (anonymous):

2/-2 = ...?

OpenStudy (dumbcow):

yes

OpenStudy (anonymous):

-1

OpenStudy (anonymous):

-1

OpenStudy (dumbcow):

yep

OpenStudy (anonymous):

Soo wha now?

OpenStudy (dumbcow):

we have to find y-intercept y=mx+b use point (0,5) m = -1 solve for b

OpenStudy (anonymous):

I forgot how :P

OpenStudy (dumbcow):

just plug in what you know m=-1 x = 0 y=5

OpenStudy (anonymous):

5= -1+0 So it would be 6?

OpenStudy (dumbcow):

mx means m*x --> (-1)(0) = 0

OpenStudy (anonymous):

So b - 5

OpenStudy (anonymous):

b = 5

OpenStudy (dumbcow):

yep b=5 also notice on your graph this line segment crosses y-axis at y=5 right?

OpenStudy (anonymous):

yes

OpenStudy (dumbcow):

thats what "b" is, the point where the line crosses y-axis

OpenStudy (dumbcow):

ok so whats the equation of this line and is triangle above or below

OpenStudy (anonymous):

idk the equation but its but its below?

OpenStudy (dumbcow):

equation y=mx +b (memorize this) plug in m and b that we solved for

OpenStudy (anonymous):

im confused

OpenStudy (dumbcow):

whats confusing what is m? what is b?

OpenStudy (anonymous):

m slope y yintercept

OpenStudy (dumbcow):

good and what values do we find

OpenStudy (anonymous):

m=-1 x = 0 y=5

OpenStudy (dumbcow):

yes and b = 5 too so y = -1x + 5

OpenStudy (dumbcow):

see where -1 and 5 replaced m and b

OpenStudy (anonymous):

y >= -1x+5?

OpenStudy (dumbcow):

perfect you changed your answer, it is actually above

OpenStudy (anonymous):

so the inequality I wrrote is right? I gave youu a medal (:

OpenStudy (dumbcow):

yes if you draw a vertical line through the line segment, if the triangle part is above intersection point then inequality is ">"

OpenStudy (dumbcow):

now you are done The points inside triangle are the only points which satisfy all 3 of these inequalities hopefully you understand writing an equation of a line given 2 points a little better

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