Question

3-10x>1
= x<1/5 ?

Answer 1

You are correct. The solution is \[\large x < \frac{1}{5}\]

Answer 2

thanks Jim. could you help me with another problem I had?

Answer 3

Ask away

Answer 4

sure

Answer 5

i need him and his fancy equation explaining skills lol

Answer 6

oh okay that's fine lol I'll watch too

Answer 7

jim* I'm trying to solve 1/(x-1)+1/4x =3

Answer 8

is the second fraction \[\frac{1}{4x}\] or \[\frac{1}{4}x\] ??

Answer 9

first

Answer 10

sorry should of used ()

Answer 11

ok, we have two options when it comes to solving equations like this

Answer 12

we can combine the fractions, then cross multiply, OR we can clear out the fractions and just get rid of them

Answer 13

I like the second option better

Answer 14

I like the latter!

Answer 15

so I'm going to with option #2


Notice how the LCD is 4x(x-1), so if we multiply EVERY term by the LCD, this will clear out the fractions.


So multiply the first fraction \[\frac{1}{x-1}\] by \[4x(x-1)\] to get \[4x(x-1)\left(\frac{1}{x-1}\right)=\frac{4x(x-1)}{x-1}=4x\]


So after multiplying the first term \[\frac{1}{x-1}\] by the LCD, the denominator is now gone. So the fraction has been cleared away.

Answer 16

Do this with the rest of the terms as well.


Multiply \[\frac{1}{4x}\] with \[4x(x-1)\] to get \[x-1\]


and multiply 3 (the term on the right side) with the LCD to get \[3*4x(x-1)=12x(x-1)\]

Answer 17

oh I see. sort of.

Answer 18

So after multiplying EVERY term by the LCD, we now have the equation

\[4x+x-1=12x(x-1)\]


Do you see where to go from here?

Answer 19

yeah, they cancel nicely. Your methods of explaining own. Can you tell me how you use the equation button to show division so neatly?

Answer 20

Another way to think about it: If you multiply both sides (then distribute if needed) by the LCD, this is the same as "multiply EVERY term by the LCD", but I like the first way because if you do EVERY term, then you won't miss any terms

Answer 21

and is 12x(x-1) = 12x^2-12x?

Answer 22

At the bottom of the text box where you type your response is the "Equation" button (with a funky looking E to the left of it). Click that to get all the symbols you need.

Answer 23

yes 12x(x-1) = 12x(x)+12x(-1) = 12x^2-12x

Answer 24

yeah, but I can't find how to divide like you do, with the line of divison, i can only find the divison symbol

Answer 25

to solve this I think I need the quadratic...

Answer 26

ok, then you'll have to do it manually


type \ then a [ to start the code


Then type "\frac{1}{2}" (without quotes)


Now type \ followed by a ] to end the code


All this looks like: \ [\frac{1}{2}\ ] but without the spaces


And it renders to \[\frac{1}{2}\]

Answer 27

\[\frac{1}{2}\]

Answer 28

nice :)

Answer 29

Something more complicated


\ [\frac{x^2-x+\sqrt{12}}{\sqrt[3]{x^5}-\sin(x)}\ ]

renders to

\[\frac{x^2-x+\sqrt{12}}{\sqrt[3]{x^5}-\sin(x)}\]

Answer 30

good you got it

Answer 31

neato :D

Answer 32

so for my problem I got 5x-1=12x²-12x

Answer 33

^what you got?

Answer 34

good, that's what I got as well, so what's next

Answer 35

12x²-17x+1 =0

Answer 36

good, and then from there you can either factor, complete the square, graph or use the quadratic formula to solve. I prefer the quadratic formula.

Answer 37

yeah.. I hate it lol

Answer 38

[\frac{17±√17²-4(12)(1)}{2(12)}\]

Answer 39

booo didn't work

Answer 40

ok one sec

Answer 41

\[\frac{17±√17²-4(12)(1)}{\2(12)}\]

Answer 42

\[\frac{17±√17²-4(12)(1)}{2(12)}\]

Answer 43

\[\frac{17±\sqrt{17²-4(12)(1)}}{2(12)}\]

Answer 44

okay jim, thanks a whole bunch, but I have to run. I have a meeting with a college advisor.

Answer 45

ok will post solution in a sec

Answer 46

Solutions are \[x=\frac{17+\sqrt{241}}{24}\] or \[x=\frac{17-\sqrt{241}}{24}\]

See attached image for how I got those answers.

Answer 47

\[\frac{1}{x}\ + \frac{1}{2x}\ + \frac{1}{3x}=12\]
I ended up with 3x(24x-3) can you tell me if I'm right or if I made a mistake or if i can be factored further?

Answer 48

sry I completely forget the problem lol, one sec while I look at it

Answer 49

yeah it's lost in this mess, can you post it again?

Answer 50

haha, no no, I don't wanna do the old one.

Answer 51

I just posted that one ^ lol but I meant to do it in a new question. Lost the code haha

Answer 52

so the problem is \[\frac{1}{x}\ + \frac{1}{2x}\ + \frac{1}{3x}=12\] right?

Answer 53

sure is.

Answer 54

you want to work it here or in that new question you just asked?