Write a quadratic equation in the variable x having the given number as solutions. Type the equation in standard form,ax^2+bx+c=0
Solution:3, only solution.

Question

Write a quadratic equation in the variable x having the given number as solutions. Type the equation in standard form,ax^2+bx+c=0 
Solution:3, only solution.

jim_thompson5910 · Answer

x=3 or x=3 (note: this is a double root)


x-3=0 or x-3=0


(x-3)(x-3)=0 (I'm using the zero product property here)


x^2-6x+9=0


So the answer is $$\large x^2-6x+9=0$$

anonymous · Answer

2x^2+x-27=0 can be an answer. there are infinite possible anwers, actually :)

anonymous · Answer

Or (x - 3)(x - 3) can also be written as $$(x -3)^{2}$$ which also gives you $$x ^{2}-6x + 9$$

anonymous · Answer

I don't see how that hold's true

anonymous · Answer

Problem states that the only solution is 3

jim_thompson5910 · Answer

There are an infinite number of answers, but they are all scalar multiples of $$\large x^2-6x+9$$

Unfortunately since $$2x^2+x-27$$ is not a scalar multiple of the first expression, this means that this isn't one of them (note: roots of this polynomial involve radicals, so the roots aren't as simple)

anonymous · Answer

Yes I just checked and 2x^2 + x - 27 is not factorable