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OpenStudy (anonymous):
start with x=w^2
OpenStudy (anonymous):
solve for x as a quadratic equation
OpenStudy (anonymous):
x^2-6x-2
OpenStudy (anonymous):
Because the highest degree is 4 you should expect 4 solutions. But to begin with we will let x = w^2
x^2 - 6x - 2 = 0
Using the quadratic formula we get the result:
\[3\pm \sqrt{11}\] This is a real solution therefore the other two solutions will be complex
OpenStudy (anonymous):
thats saying that x^2 = 3+- sqroot of x or did you do it twice
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OpenStudy (anonymous):
you'd have to take the answer you get for the quadratic equation and take the square root of that
OpenStudy (anonymous):
to get x
OpenStudy (anonymous):
well i mean w^2 because you used substitution x=w^2 and you are trying to find w. so you have to take the sqroot of x
OpenStudy (anonymous):
Yes I skipped that step....
OpenStudy (anonymous):
you sould get 4 answers however 2 are non real so you are only goin to get 2
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