Question

If the impedance of a resistor in a circuit is Z₁=5+2i ohms and the impedance of a second resistor is Z₂=(3-i) ohms, find the total impedance of the two resistors when they are placed in series (the sum of the two impedances).
Total of the two resistors in a series: ??ohms
(Simplify in terms of i)

Answer 1

8-i

Answer 2

nope, not it...

Answer 3

\[Z_{1}+Z_{2}\]


\[(5+2i)+(3-i)\]


\[(5+3)+(2i-i)\]


\[8+i\]
So \[Z_{1}+Z_{2}=8+i\]