Ask your own question, for FREE!
Mathematics 22 Online
OpenStudy (anonymous):

√9x+81=x+5

OpenStudy (anonymous):

What would you do?

OpenStudy (anonymous):

subtract 5 from both sides

OpenStudy (anonymous):

good

OpenStudy (anonymous):

\[\sqrt{9} x+76=x\]

OpenStudy (anonymous):

what's next?

OpenStudy (waheguru):

looks hard

OpenStudy (anonymous):

yeah I am confused from that point.

OpenStudy (anonymous):

well if you knew to subtract 5...why not subtract 76 now?

OpenStudy (anonymous):

√9x=x

OpenStudy (anonymous):

from both sides

OpenStudy (anonymous):

but I think that is wrong.

OpenStudy (anonymous):

√9x = x - 76.....now how do you get rid of square roots?

OpenStudy (anonymous):

lost again.

OpenStudy (anonymous):

okay...u subtracted 5 from both sides correct?

OpenStudy (anonymous):

yeah i did that.

OpenStudy (anonymous):

okay...now you want to get the square root alone...so you need to subtract 76 from both sides...

OpenStudy (anonymous):

so your going from √9x + 76 = x and when you subtract 76 from both sides...your left with √9x = x -76

OpenStudy (anonymous):

now what do we do about this square root?

OpenStudy (anonymous):

1/2(161+3√313) that is what I keep getting.

OpenStudy (anonymous):

okay...well lets slow down...

OpenStudy (anonymous):

do you know how to remove the square root?

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

okay...when you have addition...you subtract from both side right?

OpenStudy (anonymous):

right

OpenStudy (anonymous):

so when you have a square root....you square both sides

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

so now that we square both sides...we get 9x = (x-76)^2

OpenStudy (anonymous):

I have 20 minutes to get this done.

OpenStudy (anonymous):

what next?

OpenStudy (anonymous):

i am going to make a guess that this is \[\sqrt{9x+81}=x+5\] am i right?

OpenStudy (anonymous):

that is the right problem

OpenStudy (anonymous):

thougth so nice integer solution square both sides as stop one

OpenStudy (anonymous):

get \[9x+81=(x+5)^2\]

OpenStudy (anonymous):

right

OpenStudy (anonymous):

then expand and get \[9x+81=x^2+10x+25\]

OpenStudy (anonymous):

right

OpenStudy (anonymous):

okay...the way you wrote the question dude....i didn't realize the 81 was under the square root

OpenStudy (anonymous):

but follow satellite...he won't steer you wrong

OpenStudy (anonymous):

let me re write it

OpenStudy (anonymous):

put all terms on one side of equation and solve the quadratic \[x^2+x-56=0\]

OpenStudy (anonymous):

\[\sqrt{9x+81}=x+5\]

OpenStudy (anonymous):

factor and solve, then check your answer

OpenStudy (anonymous):

-8 and 7 is what I am getting

OpenStudy (anonymous):

other way around

OpenStudy (anonymous):

still saying it is wrong. I am so lost.

OpenStudy (anonymous):

cause u got your answers backwards....its 8 and -7

OpenStudy (anonymous):

you are not done yet

OpenStudy (anonymous):

you have to check the answers in original equation

OpenStudy (anonymous):

I did it both ways and it said i was wrong

OpenStudy (anonymous):

now you have to check your answers as satellite is saying

OpenStudy (anonymous):

check your answers in \[\sqrt{9x+81}=x+5\]

OpenStudy (anonymous):

-7 will not work

OpenStudy (anonymous):

is 8 the answer

OpenStudy (anonymous):

reason being that step one was square, so you introduced and extraneous root

OpenStudy (anonymous):

I checked it and it is not coming out right

OpenStudy (anonymous):

I only have 15 minutes left

OpenStudy (anonymous):

solution is 7

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!