Question

Solve
w^4-6w^2-2=0

Answer 1

this one is wierd.

Answer 2

yeah I know I am really stuck

Answer 3

that is wrong.

Answer 4

you can use "quadratic" formula

Answer 5

let x be w^2, giving you x^2-6x-2=0
\[x=(-(-6)\pm \sqrt{(-6)^{2}-4(1)(-2)})\div(2)(1)\]
x=\[3 \pm \sqrt{10}\]
=w^2

\[w=\sqrt{3\pm \sqrt{10}}\]

but the answer in null set because substituting the answer wont get =0 (extraneous solution)

Answer 6

*is null set

Answer 7

Um... if you use the quadratic formula, you should get:\[w^2 = 3\pm \sqrt{11}\]\[w=\pm \sqrt{3\pm sqrt{11}}\]

The plus-minus under the square root must be a plus. But, yes. There are two solutions.