Question

what is the distance between the z-intercept from the x-intercept in the equation ax+by+cz+d=0

Answer 1

the z intercept will occur when x and y are both 0, so we get:
cz+d = 0
z = -(d/c)

the x intercept is when y and z = 0, so we get:
ax +d = 0
x = -(d/a)

using the pythagorean theorem we obtain:
\[distance = \sqrt{(-\frac{d}{c})^2+(-\frac{d}{a})^2} = d\sqrt{\frac{1}{c^2}+\frac{1}{a^2}}\]

Answer 2

tats it....
full ans is nt displayd...

Answer 3

thts right answer riya

Answer 4

k k thank u....