Question

some 1 try this or help me

Answer 1

http://i1134.photobucket.com/albums/m613/kingkos14/IMG_0003.jpg?t=1313690563

Answer 2

click it

Answer 3

how many strands of rope support 600-n weight? like that

Answer 4

what is strands im not fluent in english

Answer 5

strands is strings, or ropes

Answer 6

and we need more to go off of than your picture tells us 8(

Answer 7

even me scare to answer hahaha im always trick with my answer

Answer 8

in the first question i think 1 strands of rope but if some1 answer i think i will understand

Answer 9

2)100,100,50
3)a 1
b 100
c 100

Answer 10

thats all i go and i'm not 100% on that

Answer 11

1 strands of rope what is strands again?

Answer 12

a strad of rope would be a single rope

Answer 13

thx for the answer mam or sir?

Answer 14

good luck

Answer 15

do you know how to get letter d?

Answer 16

The sum of the forces on the weight must be equal.
In (a) the force down is 100 N, and the rope must pull up by 100N
the person must pull by 100 N.
In (b), the force down in 100 N. The rope has 2 strands pulling up. The force on the 2 strands are equal (else it would spin, or have torque).
The person must pull up 50 N
(c) again, 2 strands on the weight, each with 50 N
the person pulls 50 N

Answer 17

if the man pulls his end down 60 cm how many cm will the weight rise?

Answer 18

how many pullys?

Answer 19

1 pull

Answer 20

60cm

Answer 21

Go find some string and do the experiment.

Answer 22

i dont know i just read letter d hahahah im not fluent in english hahaaha

Answer 23

but how many cm will the weight rise in the picture

Answer 24

letter d

Answer 25

lets go with 10 cm

Answer 26

ok

Answer 27

zbay can u help me to with my last page of my homework i will do the other page promise

Answer 28

I will try

Answer 29

will i put now?

Answer 30

u want to see?

Answer 31

sure

Answer 32

http://i1134.photobucket.com/albums/m613/kingkos14/IMG_0004.jpg?t=1313690989

Answer 33

Your best bet is going to be sweet talking phi into helping you here.

but lets see what i come up with

Answer 34

ok ok =)

Answer 35

so
v=distance/time
gravity is -9.8m^2

Answer 36

ok at 1 sec v=1 2 sec v=2 3 sec v=3

Answer 37

so you start at 1 sec master zbay =) w8 i will put

Answer 38

put a zero behind all those

Answer 39

aug 25 is my sem break so i finish all my work im getting excited this is my last home work =) i always hang up here

Answer 40

zero where master zbay?

Answer 41

alright i changed my mind again, if we go (v=distance/time) we get 10 for 1,2,3 sec 0 for 0 sec and thats all i got for v=

Answer 42

ok i write it master zbay =)

Answer 43

momentum something like kg to m/s i dont know...

Answer 44

You're going to have to get someone else to help you i don't want to stear you wrong buddy

Answer 45

physics is crazy right hahaha

Answer 46

i'm pretty sure i got the v right for the first 3 sec, as long as they dont worry about the aceleration

Answer 47

yah i think your correct 100 %

Answer 48

but i don't see how you can get momentum with out firguring out your acel, because it's delta (m)(v)

Answer 49

me too TT maybe lets get back to my 1st question letter d, e , and f

Answer 50

is it the first derivitive or the 2nd derivative for acceleration?

Answer 51

ic i remember something colission or initial or final velocity

Answer 52

i would repost your 2nd paper and see what other people come up with

Answer 53

ok ok
lets see your good in english u can help me to talk to them

Answer 54

zbay

Answer 55

i post the last page try to answer the question here letter d e and f pls

Answer 56

master zbay is sleeping hahaha